3k-2=2(-k+2)

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Solution for 3k-2=2(-k+2) equation: 



3k-2=2(-k+2)

We move all terms to the left:

3k-2-(2(-k+2))=0

We add all the numbers together, and all the variables

3k-(2(-1k+2))-2=0



We calculate terms in parentheses: -(2(-1k+2)), so:

2(-1k+2)

We multiply parentheses

-2k+4

Back to the equation:

-(-2k+4)



We get rid of parentheses

3k+2k-4-2=0

We add all the numbers together, and all the variables

5k-6=0

We move all terms containing k to the left, all other terms to the right

5k=6

k=6/5

k=1+1/5

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