3k-4/k+1=0k=

Solution for 3k-4/k+1=0k= equation:

3k-4/k+1=0k=

We move all terms to the left:

3k-4/k+1-(0k)=0


Domain of the equation: k!=0

k∈R


We add all the numbers together, and all the variables

2k-4/k+1=0

We multiply all the terms by the denominator


2k*k+1*k-4=0

We add all the numbers together, and all the variables

k+2k*k-4=0

Wy multiply elements

2k^2+k-4=0

a = 2; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·2·(-4)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{33}}{2*2}=\frac{-1-\sqrt{33}}{4}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{33}}{2*2}=\frac{-1+\sqrt{33}}{4}
$