3k/4=(k-14)/6

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Solution for 3k/4=(k-14)/6 equation: 



3k/4=(k-14)/6

We move all terms to the left:

3k/4-((k-14)/6)=0

We calculate fractions


18k^2/()+(-((k-14)*4)/()=0



We calculate terms in parentheses: +(-((k-14)*4)/(), so:

-((k-14)*4)/(

We multiply all the terms by the denominator


-((k-14)*4)



We calculate terms in parentheses: -((k-14)*4), so:

(k-14)*4

We multiply parentheses

4k-56

Back to the equation:

-(4k-56)



We get rid of parentheses

-4k+56

Back to the equation:

+(-4k+56)



We get rid of parentheses

18k^2/()-4k+56=0

We multiply all the terms by the denominator


18k^2-4k*()+56*()=0

We add all the numbers together, and all the variables

18k^2-4k*()=0

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