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3k^2+5k-22=0
a = 3; b = 5; c = -22;
Δ = b2-4ac
Δ = 52-4·3·(-22)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-17}{2*3}=\frac{-22}{6} =-3+2/3 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+17}{2*3}=\frac{12}{6} =2 $
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