3k2/3=27

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Solution for 3k2/3=27 equation: 


k in (-oo:+oo)

(3*k^2)/3 = 27 // - 27

(3*k^2)/3-27 = 0

1*k^2 = 27 // : 1

k^2 = 27

k^2 = 27 // ^ 1/2

abs(k) = 3*3^(1/2)

k = 3*3^(1/2) or k = -(3*3^(1/2))

k in { 3*3^(1/2), -(3*3^(1/2)) }

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