3l+3(l-7)=135

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Solution for 3l+3(l-7)=135 equation: 



3l+3(l-7)=135

We move all terms to the left:

3l+3(l-7)-(135)=0

We multiply parentheses

3l+3l-21-135=0

We add all the numbers together, and all the variables

6l-156=0

We move all terms containing l to the left, all other terms to the right

6l=156

l=156/6

l=26

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