3l+3(l-7)=135

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Solution for 3l+3(l-7)=135 equation:



3l+3(l-7)=135
We move all terms to the left:
3l+3(l-7)-(135)=0
We multiply parentheses
3l+3l-21-135=0
We add all the numbers together, and all the variables
6l-156=0
We move all terms containing l to the left, all other terms to the right
6l=156
l=156/6
l=26

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