3log(4)(3q+1)=9

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Solution for 3log(4)(3q+1)=9 equation:


Simplifying
3log(4)(3q + 1) = 9

Reorder the terms:
3glo * 4(1 + 3q) = 9

Reorder the terms for easier multiplication:
3 * 4glo(1 + 3q) = 9

Multiply 3 * 4
12glo(1 + 3q) = 9
(1 * 12glo + 3q * 12glo) = 9
(12glo + 36gloq) = 9

Solving
12glo + 36gloq = 9

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-9 + 12glo + 36gloq = 9 + -9

Combine like terms: 9 + -9 = 0
-9 + 12glo + 36gloq = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(-3 + 4glo + 12gloq) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(-3 + 4glo + 12gloq)' equal to zero and attempt to solve: Simplifying -3 + 4glo + 12gloq = 0 Solving -3 + 4glo + 12gloq = 0 Move all terms containing g to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 4glo + 3 + 12gloq = 0 + 3 Reorder the terms: -3 + 3 + 4glo + 12gloq = 0 + 3 Combine like terms: -3 + 3 = 0 0 + 4glo + 12gloq = 0 + 3 4glo + 12gloq = 0 + 3 Combine like terms: 0 + 3 = 3 4glo + 12gloq = 3 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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