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3m(m-14)=0
We multiply parentheses
3m^2-42m=0
a = 3; b = -42; c = 0;
Δ = b2-4ac
Δ = -422-4·3·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-42}{2*3}=\frac{0}{6} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+42}{2*3}=\frac{84}{6} =14 $
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