3m(m-2)=12m

Solution for 3m(m-2)=12m equation:

3m(m-2)=12m

We move all terms to the left:

3m(m-2)-(12m)=0

We add all the numbers together, and all the variables

-12m+3m(m-2)=0

We multiply parentheses

3m^2-12m-6m=0

We add all the numbers together, and all the variables

3m^2-18m=0

a = 3; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·3·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*3}=\frac{0}{6}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*3}=\frac{36}{6}
=6
$