3m+(-2)=19

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Solution for 3m+(-2)=19 equation: 



3m+(-2)=19

We move all terms to the left:

3m+(-2)-(19)=0

determiningTheFunctionDomain
3m-19+(-2)=0

We add all the numbers together, and all the variables

3m-21=0

We move all terms containing m to the left, all other terms to the right

3m=21

m=21/3

m=7

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