3m+12=3(4+m)

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Solution for 3m+12=3(4+m) equation: 



3m+12=3(4+m)

We move all terms to the left:

3m+12-(3(4+m))=0

We add all the numbers together, and all the variables

3m-(3(m+4))+12=0



We calculate terms in parentheses: -(3(m+4)), so:

3(m+4)

We multiply parentheses

3m+12

Back to the equation:

-(3m+12)



We get rid of parentheses

3m-3m-12+12=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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