3m+2(m-4)=-2(m-2)-6

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Solution for 3m+2(m-4)=-2(m-2)-6 equation:



3m+2(m-4)=-2(m-2)-6
We move all terms to the left:
3m+2(m-4)-(-2(m-2)-6)=0
We multiply parentheses
3m+2m-(-2(m-2)-6)-8=0
We calculate terms in parentheses: -(-2(m-2)-6), so:
-2(m-2)-6
We multiply parentheses
-2m+4-6
We add all the numbers together, and all the variables
-2m-2
Back to the equation:
-(-2m-2)
We add all the numbers together, and all the variables
5m-(-2m-2)-8=0
We get rid of parentheses
5m+2m+2-8=0
We add all the numbers together, and all the variables
7m-6=0
We move all terms containing m to the left, all other terms to the right
7m=6
m=6/7
m=6/7

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