3m+2m(m-5)=10

Solution for 3m+2m(m-5)=10 equation:

3m+2m(m-5)=10

We move all terms to the left:

3m+2m(m-5)-(10)=0

We multiply parentheses

2m^2+3m-10m-10=0

We add all the numbers together, and all the variables

2m^2-7m-10=0

a = 2; b = -7; c = -10;
Δ = b2-4ac
Δ = -72-4·2·(-10)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{129}}{2*2}=\frac{7-\sqrt{129}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{129}}{2*2}=\frac{7+\sqrt{129}}{4}
$