3m+3(2m-6)=7m+4(m+3)

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Solution for 3m+3(2m-6)=7m+4(m+3) equation: 



3m+3(2m-6)=7m+4(m+3)

We move all terms to the left:

3m+3(2m-6)-(7m+4(m+3))=0

We multiply parentheses

3m+6m-(7m+4(m+3))-18=0



We calculate terms in parentheses: -(7m+4(m+3)), so:

7m+4(m+3)

We multiply parentheses

7m+4m+12

We add all the numbers together, and all the variables

11m+12

Back to the equation:

-(11m+12)



We add all the numbers together, and all the variables

9m-(11m+12)-18=0

We get rid of parentheses

9m-11m-12-18=0

We add all the numbers together, and all the variables

-2m-30=0

We move all terms containing m to the left, all other terms to the right

-2m=30

m=30/-2

m=-15

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