3m+3+6m=-6(-4-2m)+4(1-2m)

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Solution for 3m+3+6m=-6(-4-2m)+4(1-2m) equation: 



3m+3+6m=-6(-4-2m)+4(1-2m)

We move all terms to the left:

3m+3+6m-(-6(-4-2m)+4(1-2m))=0

We add all the numbers together, and all the variables

3m+6m-(-6(-2m-4)+4(-2m+1))+3=0

We add all the numbers together, and all the variables

9m-(-6(-2m-4)+4(-2m+1))+3=0



We calculate terms in parentheses: -(-6(-2m-4)+4(-2m+1)), so:

-6(-2m-4)+4(-2m+1)

We multiply parentheses

12m-8m+24+4

We add all the numbers together, and all the variables

4m+28

Back to the equation:

-(4m+28)



We get rid of parentheses

9m-4m-28+3=0

We add all the numbers together, and all the variables

5m-25=0

We move all terms containing m to the left, all other terms to the right

5m=25

m=25/5

m=5

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