3m+5(m-4)=2m+2(20+2)

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Solution for 3m+5(m-4)=2m+2(20+2) equation: 



3m+5(m-4)=2m+2(20+2)

We move all terms to the left:

3m+5(m-4)-(2m+2(20+2))=0

We add all the numbers together, and all the variables

3m+5(m-4)-(2m+222)=0

We multiply parentheses

3m+5m-(2m+222)-20=0

We get rid of parentheses

3m+5m-2m-222-20=0

We add all the numbers together, and all the variables

6m-242=0

We move all terms containing m to the left, all other terms to the right

6m=242

m=242/6

m=40+1/3

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