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3m+5=8/m
We move all terms to the left:
3m+5-(8/m)=0
Domain of the equation: m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
3m-(+8/m)+5=0
We get rid of parentheses
3m-8/m+5=0
We multiply all the terms by the denominator
3m*m+5*m-8=0
We add all the numbers together, and all the variables
5m+3m*m-8=0
Wy multiply elements
3m^2+5m-8=0
a = 3; b = 5; c = -8;
Δ = b2-4ac
Δ = 52-4·3·(-8)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-11}{2*3}=\frac{-16}{6} =-2+2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+11}{2*3}=\frac{6}{6} =1 $
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