3m-(7m+12)=2(m-3)*

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Solution for 3m-(7m+12)=2(m-3)* equation: 



3m-(7m+12)=2(m-3)*

We move all terms to the left:

3m-(7m+12)-(2(m-3)*)=0

We get rid of parentheses

3m-7m-(2(m-3)*)-12=0



We calculate terms in parentheses: -(2(m-3)*), so:

2(m-3)*

We multiply parentheses

2m-6

Back to the equation:

-(2m-6)



We add all the numbers together, and all the variables

-4m-(2m-6)-12=0

We get rid of parentheses

-4m-2m+6-12=0

We add all the numbers together, and all the variables

-6m-6=0

We move all terms containing m to the left, all other terms to the right

-6m=6

m=6/-6

m=-1

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