3m-27=2(m+5)-2

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Solution for 3m-27=2(m+5)-2 equation: 



3m-27=2(m+5)-2

We move all terms to the left:

3m-27-(2(m+5)-2)=0



We calculate terms in parentheses: -(2(m+5)-2), so:

2(m+5)-2

We multiply parentheses

2m+10-2

We add all the numbers together, and all the variables

2m+8

Back to the equation:

-(2m+8)



We get rid of parentheses

3m-2m-8-27=0

We add all the numbers together, and all the variables

m-35=0

We move all terms containing m to the left, all other terms to the right

m=35

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