3m-6(4m+1)=99

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Solution for 3m-6(4m+1)=99 equation: 



3m-6(4m+1)=99

We move all terms to the left:

3m-6(4m+1)-(99)=0

We multiply parentheses

3m-24m-6-99=0

We add all the numbers together, and all the variables

-21m-105=0

We move all terms containing m to the left, all other terms to the right

-21m=105

m=105/-21

m=-5

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