3m-7m+12=2(m-3)

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Solution for 3m-7m+12=2(m-3) equation: 



3m-7m+12=2(m-3)

We move all terms to the left:

3m-7m+12-(2(m-3))=0

We add all the numbers together, and all the variables

-4m-(2(m-3))+12=0



We calculate terms in parentheses: -(2(m-3)), so:

2(m-3)

We multiply parentheses

2m-6

Back to the equation:

-(2m-6)



We get rid of parentheses

-4m-2m+6+12=0

We add all the numbers together, and all the variables

-6m+18=0

We move all terms containing m to the left, all other terms to the right

-6m=-18

m=-18/-6

m=+3

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