3m-8/m+2=4

Solution for 3m-8/m+2=4 equation:

3m-8/m+2=4

We move all terms to the left:

3m-8/m+2-(4)=0


Domain of the equation: m!=0

m∈R


We add all the numbers together, and all the variables

3m-8/m-2=0

We multiply all the terms by the denominator


3m*m-2*m-8=0

We add all the numbers together, and all the variables

-2m+3m*m-8=0

Wy multiply elements

3m^2-2m-8=0

a = 3; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·3·(-8)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*3}=\frac{-8}{6}
=-1+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*3}=\frac{12}{6}
=2
$