3m2+5m=m2-7m-18

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Solution for 3m2+5m=m2-7m-18 equation: 



3m^2+5m=m2-7m-18

We move all terms to the left:

3m^2+5m-(m2-7m-18)=0

We add all the numbers together, and all the variables

3m^2-(+m^2-7m-18)+5m=0

We get rid of parentheses

3m^2-m^2+7m+5m+18=0

We add all the numbers together, and all the variables

2m^2+12m+18=0

a = 2; b = 12; c = +18;
Δ = b2-4ac
Δ = 122-4·2·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{-12}{4}=-3$

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