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3m^2-22=-7m
We move all terms to the left:
3m^2-22-(-7m)=0
We get rid of parentheses
3m^2+7m-22=0
a = 3; b = 7; c = -22;
Δ = b2-4ac
Δ = 72-4·3·(-22)
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{313}}{2*3}=\frac{-7-\sqrt{313}}{6} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{313}}{2*3}=\frac{-7+\sqrt{313}}{6} $
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