3m2-m(2m-3)=m2+3m

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Solution for 3m2-m(2m-3)=m2+3m equation: 



3m^2-m(2m-3)=m2+3m

We move all terms to the left:

3m^2-m(2m-3)-(m2+3m)=0

We add all the numbers together, and all the variables

3m^2-(+m^2+3m)-m(2m-3)=0

We multiply parentheses

3m^2-(+m^2+3m)-2m^2+3m=0

We get rid of parentheses

3m^2-m^2-2m^2-3m+3m=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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