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3m^2-m-14=0
We add all the numbers together, and all the variables
3m^2-1m-14=0
a = 3; b = -1; c = -14;
Δ = b2-4ac
Δ = -12-4·3·(-14)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*3}=\frac{-12}{6} =-2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*3}=\frac{14}{6} =2+1/3 $
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