3m=125+5(m+5)

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Solution for 3m=125+5(m+5) equation: 



3m=125+5(m+5)

We move all terms to the left:

3m-(125+5(m+5))=0



We calculate terms in parentheses: -(125+5(m+5)), so:

125+5(m+5)

determiningTheFunctionDomain
5(m+5)+125

We multiply parentheses

5m+25+125

We add all the numbers together, and all the variables

5m+150

Back to the equation:

-(5m+150)



We get rid of parentheses

3m-5m-150=0

We add all the numbers together, and all the variables

-2m-150=0

We move all terms containing m to the left, all other terms to the right

-2m=150

m=150/-2

m=-75

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