3m=2(m-5)=12

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Solution for 3m=2(m-5)=12 equation: 



3m=2(m-5)=12

We move all terms to the left:

3m-(2(m-5))=0



We calculate terms in parentheses: -(2(m-5)), so:

2(m-5)

We multiply parentheses

2m-10

Back to the equation:

-(2m-10)



We get rid of parentheses

3m-2m+10=0

We add all the numbers together, and all the variables

m+10=0

We move all terms containing m to the left, all other terms to the right

m=-10

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