3m=5+(m/2)

Solution for 3m=5+(m/2) equation:

3m=5+(m/2)

We move all terms to the left:

3m-(5+(m/2))=0

We add all the numbers together, and all the variables

3m-(5+(+m/2))=0

We multiply all the terms by the denominator


3m*2))-(5+(+m=0

We add all the numbers together, and all the variables

m+3m*2))-(5+(=0

Wy multiply elements

6m^2+m=0

a = 6; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·6·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*6}=\frac{-2}{12}
=-1/6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*6}=\frac{0}{12}
=0
$