3n+(3n+3)=141

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Solution for 3n+(3n+3)=141 equation: 



3n+(3n+3)=141

We move all terms to the left:

3n+(3n+3)-(141)=0

We get rid of parentheses

3n+3n+3-141=0

We add all the numbers together, and all the variables

6n-138=0

We move all terms containing n to the left, all other terms to the right

6n=138

n=138/6

n=23

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