3n+-2=(3n+3)+-5

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Solution for 3n+-2=(3n+3)+-5 equation: 



3n+-2=(3n+3)+-5

We move all terms to the left:

3n+-2-((3n+3)+-5)=0

We add all the numbers together, and all the variables

3n-((3n+3)+-5)=0

We use the square of the difference formula

3n-((3n+3)-5)=0



We calculate terms in parentheses: -((3n+3)-5), so:

(3n+3)-5

We get rid of parentheses

3n+3-5

We add all the numbers together, and all the variables

3n-2

Back to the equation:

-(3n-2)



We get rid of parentheses

3n-3n+2=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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