3n+14-5n=2(2n-4)-2n+14=4n-18

Solution for 3n+14-5n=2(2n-4)-2n+14=4n-18 equation:

3n+14-5n=2(2n-4)-2n+14=4n-18

We move all terms to the left:

3n+14-5n-(2(2n-4)-2n+14)=0

We add all the numbers together, and all the variables

-2n-(2(2n-4)-2n+14)+14=0


We calculate terms in parentheses: -(2(2n-4)-2n+14), so:

2(2n-4)-2n+14

We add all the numbers together, and all the variables

-2n+2(2n-4)+14

We multiply parentheses

-2n+4n-8+14

We add all the numbers together, and all the variables

2n+6

Back to the equation:

-(2n+6)


We get rid of parentheses

-2n-2n-6+14=0

We add all the numbers together, and all the variables

-4n+8=0

We move all terms containing n to the left, all other terms to the right

-4n=-8

n=-8/-4

n=+2