3n+1=3(n-1)+4

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Solution for 3n+1=3(n-1)+4 equation: 



3n+1=3(n-1)+4

We move all terms to the left:

3n+1-(3(n-1)+4)=0



We calculate terms in parentheses: -(3(n-1)+4), so:

3(n-1)+4

We multiply parentheses

3n-3+4

We add all the numbers together, and all the variables

3n+1

Back to the equation:

-(3n+1)



We get rid of parentheses

3n-3n-1+1=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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