3n+2(n+4)=64

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Solution for 3n+2(n+4)=64 equation: 



3n+2(n+4)=64

We move all terms to the left:

3n+2(n+4)-(64)=0

We multiply parentheses

3n+2n+8-64=0

We add all the numbers together, and all the variables

5n-56=0

We move all terms containing n to the left, all other terms to the right

5n=56

n=56/5

n=11+1/5

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