3n+2(n-)=4n-1

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Solution for 3n+2(n-)=4n-1 equation: 



3n+2(n-)=4n-1

We move all terms to the left:

3n+2(n-)-(4n-1)=0

We add all the numbers together, and all the variables

3n+2(+n)-(4n-1)=0

We multiply parentheses

3n+2n-(4n-1)=0

We get rid of parentheses

3n+2n-4n+1=0

We add all the numbers together, and all the variables

n+1=0

We move all terms containing n to the left, all other terms to the right

n=-1

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