3n+2(n-2)=4n2

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Solution for 3n+2(n-2)=4n2 equation: 



3n+2(n-2)=4n^2

We move all terms to the left:

3n+2(n-2)-(4n^2)=0

determiningTheFunctionDomain
-4n^2+3n+2(n-2)=0

We multiply parentheses

-4n^2+3n+2n-4=0

We add all the numbers together, and all the variables

-4n^2+5n-4=0

a = -4; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·(-4)·(-4)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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