3n+2+n=2(2n+1)5n+7

Solution for 3n+2+n=2(2n+1)5n+7 equation:

3n+2+n=2(2n+1)5n+7

We move all terms to the left:

3n+2+n-(2(2n+1)5n+7)=0

We add all the numbers together, and all the variables

4n-(2(2n+1)5n+7)+2=0


We calculate terms in parentheses: -(2(2n+1)5n+7), so:

2(2n+1)5n+7

We multiply parentheses

20n^2+10n+7

Back to the equation:

-(20n^2+10n+7)


We get rid of parentheses

-20n^2+4n-10n-7+2=0

We add all the numbers together, and all the variables

-20n^2-6n-5=0

a = -20; b = -6; c = -5;
Δ = b2-4ac
Δ = -62-4·(-20)·(-5)
Δ = -364
Delta is less than zero, so there is no solution for the equation