3n+4(n-2)=7+n

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Solution for 3n+4(n-2)=7+n equation: 



3n+4(n-2)=7+n

We move all terms to the left:

3n+4(n-2)-(7+n)=0

We add all the numbers together, and all the variables

3n+4(n-2)-(n+7)=0

We multiply parentheses

3n+4n-(n+7)-8=0

We get rid of parentheses

3n+4n-n-7-8=0

We add all the numbers together, and all the variables

6n-15=0

We move all terms containing n to the left, all other terms to the right

6n=15

n=15/6

n=2+1/2

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