3n+42=7-2(n-2)

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Solution for 3n+42=7-2(n-2) equation: 



3n+42=7-2(n-2)

We move all terms to the left:

3n+42-(7-2(n-2))=0



We calculate terms in parentheses: -(7-2(n-2)), so:

7-2(n-2)

determiningTheFunctionDomain
-2(n-2)+7

We multiply parentheses

-2n+4+7

We add all the numbers together, and all the variables

-2n+11

Back to the equation:

-(-2n+11)



We get rid of parentheses

3n+2n-11+42=0

We add all the numbers together, and all the variables

5n+31=0

We move all terms containing n to the left, all other terms to the right

5n=-31

n=-31/5

n=-6+1/5

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