3n+4n-2=(3+4)n-2=

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Solution for 3n+4n-2=(3+4)n-2= equation: 



3n+4n-2=(3+4)n-2=

We move all terms to the left:

3n+4n-2-((3+4)n-2)=0

We add all the numbers together, and all the variables

3n+4n-(7n-2)-2=0

We add all the numbers together, and all the variables

7n-(7n-2)-2=0

We get rid of parentheses

7n-7n+2-2=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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