3n+4n-2=(4+3)n-2

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Solution for 3n+4n-2=(4+3)n-2 equation: 



3n+4n-2=(4+3)n-2

We move all terms to the left:

3n+4n-2-((4+3)n-2)=0

We add all the numbers together, and all the variables

3n+4n-(7n-2)-2=0

We add all the numbers together, and all the variables

7n-(7n-2)-2=0

We get rid of parentheses

7n-7n+2-2=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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