3n+5=10+4(n-2)

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Solution for 3n+5=10+4(n-2) equation: 



3n+5=10+4(n-2)

We move all terms to the left:

3n+5-(10+4(n-2))=0



We calculate terms in parentheses: -(10+4(n-2)), so:

10+4(n-2)

determiningTheFunctionDomain
4(n-2)+10

We multiply parentheses

4n-8+10

We add all the numbers together, and all the variables

4n+2

Back to the equation:

-(4n+2)



We get rid of parentheses

3n-4n-2+5=0

We add all the numbers together, and all the variables

-1n+3=0

We move all terms containing n to the left, all other terms to the right

-n=-3

n=-3/-1

n=+3

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