3n+7=16/n

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Solution for 3n+7=16/n equation:



3n+7=16/n
We move all terms to the left:
3n+7-(16/n)=0
Domain of the equation: n)!=0
n!=0/1
n!=0
n∈R
We add all the numbers together, and all the variables
3n-(+16/n)+7=0
We get rid of parentheses
3n-16/n+7=0
We multiply all the terms by the denominator
3n*n+7*n-16=0
We add all the numbers together, and all the variables
7n+3n*n-16=0
Wy multiply elements
3n^2+7n-16=0
a = 3; b = 7; c = -16;
Δ = b2-4ac
Δ = 72-4·3·(-16)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{241}}{2*3}=\frac{-7-\sqrt{241}}{6} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{241}}{2*3}=\frac{-7+\sqrt{241}}{6} $

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