3n+9/n+3

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Solution for 3n+9/n+3 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

3*n+9/n+3 = 0

3*n^1+9*n^-1+3*n^0 = 0

(3*n^2+3*n^1+9*n^0)/(n^1) = 0 // * n^2

n^1*(3*n^2+3*n^1+9*n^0) = 0

n^1

3*n^2+3*n+9 = 0

3*n^2+3*n+9 = 0

DELTA = 3^2-(3*4*9)

DELTA = -99

DELTA < 0

n in { } 

n belongs to the empty set

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