3n-(7n+12)=2(n-3)

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Solution for 3n-(7n+12)=2(n-3) equation: 



3n-(7n+12)=2(n-3)

We move all terms to the left:

3n-(7n+12)-(2(n-3))=0

We get rid of parentheses

3n-7n-(2(n-3))-12=0



We calculate terms in parentheses: -(2(n-3)), so:

2(n-3)

We multiply parentheses

2n-6

Back to the equation:

-(2n-6)



We add all the numbers together, and all the variables

-4n-(2n-6)-12=0

We get rid of parentheses

-4n-2n+6-12=0

We add all the numbers together, and all the variables

-6n-6=0

We move all terms containing n to the left, all other terms to the right

-6n=6

n=6/-6

n=-1

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