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3n-1/2n=10
We move all terms to the left:
3n-1/2n-(10)=0
Domain of the equation: 2n!=0We multiply all the terms by the denominator
n!=0/2
n!=0
n∈R
3n*2n-10*2n-1=0
Wy multiply elements
6n^2-20n-1=0
a = 6; b = -20; c = -1;
Δ = b2-4ac
Δ = -202-4·6·(-1)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{106}}{2*6}=\frac{20-2\sqrt{106}}{12} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{106}}{2*6}=\frac{20+2\sqrt{106}}{12} $
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