3n-11=3+2(n-4)

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Solution for 3n-11=3+2(n-4) equation: 



3n-11=3+2(n-4)

We move all terms to the left:

3n-11-(3+2(n-4))=0



We calculate terms in parentheses: -(3+2(n-4)), so:

3+2(n-4)

determiningTheFunctionDomain
2(n-4)+3

We multiply parentheses

2n-8+3

We add all the numbers together, and all the variables

2n-5

Back to the equation:

-(2n-5)



We get rid of parentheses

3n-2n+5-11=0

We add all the numbers together, and all the variables

n-6=0

We move all terms containing n to the left, all other terms to the right

n=6

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