3n-1=2(n+4)

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Solution for 3n-1=2(n+4) equation: 



3n-1=2(n+4)

We move all terms to the left:

3n-1-(2(n+4))=0



We calculate terms in parentheses: -(2(n+4)), so:

2(n+4)

We multiply parentheses

2n+8

Back to the equation:

-(2n+8)



We get rid of parentheses

3n-2n-8-1=0

We add all the numbers together, and all the variables

n-9=0

We move all terms containing n to the left, all other terms to the right

n=9

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