3n-2(n+3)=14-n

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Solution for 3n-2(n+3)=14-n equation: 



3n-2(n+3)=14-n

We move all terms to the left:

3n-2(n+3)-(14-n)=0

We add all the numbers together, and all the variables

3n-2(n+3)-(-1n+14)=0

We multiply parentheses

3n-2n-(-1n+14)-6=0

We get rid of parentheses

3n-2n+1n-14-6=0

We add all the numbers together, and all the variables

2n-20=0

We move all terms containing n to the left, all other terms to the right

2n=20

n=20/2

n=10

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