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3*n-((2/9)*b) = (1/3)*b-7 // - (1/3)*b-7
3*n-((2/9)*b)-((1/3)*b)+7 = 0
(-2/9)*b+(-1/3)*b+3*n+7 = 0
3*n-5/9*b+7 = 0
x należy do R
x in (-oo:+oo)
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